the radius of first circle is 1cm and that of second circle is 1/2 cm and that of third circles if 1/4 cm till indefinitely what is the sum of the areas of the Circles
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Area of circle = π r ²
r = 1 cm
so, area of first circle is
22/7 x 1² = 3.14 cm²
area of second = 22/7 x (1/2) ²
3.14 x 0.5²
3.14 x 0.25 = 0.785 cm²
area of 3rd = 22/7 x (1/4)²
3.14 x 0.25²
3.14 x 0.0625 = 0.19625 cm²
So, 3.14 + 0.785 + 0.19625 = 4.12125 cm²
r = 1 cm
so, area of first circle is
22/7 x 1² = 3.14 cm²
area of second = 22/7 x (1/2) ²
3.14 x 0.5²
3.14 x 0.25 = 0.785 cm²
area of 3rd = 22/7 x (1/4)²
3.14 x 0.25²
3.14 x 0.0625 = 0.19625 cm²
So, 3.14 + 0.785 + 0.19625 = 4.12125 cm²
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Answer:
22/7 x 1² = 3.14 cm²
area of second = 22/7 x (1/2) ²
3.14 x 0.5²
3.14 x 0.25 = 0.785 cm²
area of 3rd = 22/7 x (1/4)²
3.14 x 0.25²
3.14 x 0.0625 = 0.19625 cm²
So, 3.14 + 0.785 + 0.19625 = 4.12125 cm²
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