Question

The radius of gyration of a disc of mass 100 gm and radius is 5 cm about an axis passing through center of gravity and perpendicular to the plane is A) 3.54 cm B) 1.54 cm​

Answer 1

Answer:—

The correct answer is 3.54 cm.

Explanation:—

The expression for the moment of inertia in terms of radius of gyration is as follows;

$I= Mk^{2}$

Here,

• M is the mass of the disc and k is the radius of gyration.

• It is given in the problem that the object is disc having mass 100 g and radius 5 cm.

Use the expression for the moment of inertia of disc.

$I= \frac{1}{2} MR^{2}$

Here,

→ R is the radius.

Put $I= \frac{1}{2} MR^{2}$ in the above expression.

$\frac{1}{2} MR^{2}= Mk^{2}$

$k^{2}=\frac{1}{2} \times (5)^{2}$

Therefore,

The value of the radius of gyration of a disc of mass about an axis is 3.5 cm.

Answer 2

Answer:

I am also fine

Step-by-step explanation:

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