The radius of gyration of a hollow sphere of radius r, about a certain axis is r. The distance of this axis from the centre of sphere is
√61/19r
√12r
√5r
√r/√3
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Given info : The radius of gyration of a hollow sphere of radius r, and a certain axis is r.
To find : the distance of this axis from the centre of sphere is ....
solution : moment of inertia of a hollow sphere with respect of centre of mass is given by, I = 2/3 mr²
where r is radius of hollow sphere and m is mass.
let the distance of the axis from centre of sphere is h.
radius of gyration is r.
so, I = mk² = mr² [radius of gyration, k = r ]
using parallel axis theorem,
I = I_cm + mh²
⇒mr² = 2/3 mr² + mh²
⇒1/3 mr² = mh²
⇒h = 1/√3 r
Therefore the distance of axis from the centre of sphere is r/√3 .
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