Question

The radius of gyration of a ring about the tangent perpendicular to its plane is ______.

Answer 1

Answer is 1.414×radius of ring

Answer 2

Dear Student,

◆ Answer -

K = √(3/2) R

● Explanation -

Let R be radius of the ring and K be its radius of gyration about the tangent perpendicular to its plane.

Moment of inertia about the tangent perpendicular to its plane is given by -

I = 3/2 MR^2

But I = MK^2,

MK^2 = 3/2 MR^2

K^2 = 3/2 R^2

K = √(3/2) R

Hence, radius of gyration is √(3/2) R.

Thanks dear. Hope this helps you...