The radius of loller is 60 cm and its length is 84 cm find the area of the ground pressed by it in 500 revolution
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roller is cylindrical shape.
given: r=60cm.
h=84cm.
curved surface area of roller =2pirh
=2*22/7*60*84
=44*60*12
=2640*12
=31680sq. cm
500*31680
=15840000.sq.cm.
therefore the area of the ground pressed by it in 500 revolution is 15840000sq. cm.
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