the radius of Na+ cation is less than that of Na atom.
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Answered by
44
ATOMIC SIZE: Distance from the nuclius to the outermost electron.
Na⁺→Loss of one electron.
The atomic radius of Na⁺ is less than that of Na,because due to the loss of 1e ⁻,the inter electronic repulsion by the electrons in the inner shell decreases.
As the interelectronic repulsion decreases, the attraction between the nuclei and the outermost electron increases,leading to the decrease in the atomic size.
NOTE:
1.Size of cation is always smaller than the parent atom.
2.Size of anioin is larger than the parent atom.
Na⁺→Loss of one electron.
The atomic radius of Na⁺ is less than that of Na,because due to the loss of 1e ⁻,the inter electronic repulsion by the electrons in the inner shell decreases.
As the interelectronic repulsion decreases, the attraction between the nuclei and the outermost electron increases,leading to the decrease in the atomic size.
NOTE:
1.Size of cation is always smaller than the parent atom.
2.Size of anioin is larger than the parent atom.
vishagh:
Hope it helped.comment in case of doubt.
Answered by
41
Na: 1s2 2s2 2p6 3s1 ....
So the outermost shell n = 3 for the outermost electron.
For Sodium ion: Na+: the outermost orbit is n = 2 only.
Thus the radius of Na+ is less than that of Sodium, as the shell 3 is not present in it.
Usually the radius of a cation is less than that of a neutral atom.
So the outermost shell n = 3 for the outermost electron.
For Sodium ion: Na+: the outermost orbit is n = 2 only.
Thus the radius of Na+ is less than that of Sodium, as the shell 3 is not present in it.
Usually the radius of a cation is less than that of a neutral atom.
click on red heart thanks above pls
Sir is less interelectronic repulsion a valid reason,incase the cation and the parent atom have same no of shells?
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