Question

The radius of nearly circular orbit of mercury is 5.8 m and its orbital period is 88 days.if a hypothetical planet has an orbital period of 55 days,what is the radius of its circular orbit?

Answer 1

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Answer 2

Answer:

Explanation:

r1cube /r2cube=t1square /t2 square , then put the value 5.8 *10to the power 10 /r2. Cube = 88 square /55 square.. .........r2 =4.3*10to the power 10

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