The radius of one circular field is 5 m and that of other is 3 m .Find the radius of the circular field whose area is the difference of areas of the first and second field
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R of 1st field = 5 cm
r of 2nd field = 3 cm
ar(1st field)-ar(2nd field) = ar(3rd field)
3.14*5*5-3.14*3*3 = ar(3rd field)
78.5-28.26 = ar(3rd field)
47.24 = ar(3rd field)
47.24/3.14 = r'^2
15.04 = r'^2
3.87 = r'
r of 2nd field = 3 cm
ar(1st field)-ar(2nd field) = ar(3rd field)
3.14*5*5-3.14*3*3 = ar(3rd field)
78.5-28.26 = ar(3rd field)
47.24 = ar(3rd field)
47.24/3.14 = r'^2
15.04 = r'^2
3.87 = r'
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