Question

the radius of one circular field is 5 M and that of other is 3 M find the radius of the circular field whose areas is a difference of area on the first and second field

Answer 1

Area of first =pi*5*5=25 pi
Area of second =pi*3*3=9 pi
Difference =16 pi
Area of third=pi*r*r
16 pi=pi*r*r
r=
$\sqrt{16 }$
r=4 m