The radius of one circular field is 5 m and that of other is 3 m. Find the radius of the circular field whose
area is the difference of the areas of the first and second field.
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Let the two circles be A and B
Area of Circle A = π r2 =3.14 x (5)^2
Area of Circle B = π r2 = 3.14 x (3)^2
Total Area = Area of Circle A - Area of Circle B
= 3.14 x (3)^2 π r2 =3.14 x (5)^2 - 3.14 x (3)^2 m^2
... Area of Circle C = 3.14 x (5)^2 - 3.14 x (3)^2 m^2 m2
π r2 =3.14 x r2 = 3.14 x (5)^2 - 3.14 x (3)^2 m^2
πr2 = 3.14 x (25-9)
3.14 x r2 = 3.14 x 16
r^2 = 16 m^2
r = 4m.
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Answer:
I think it is 13 because the question cannot be solved when it is 3.
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