The radius of one circular field is 7 m and that of another is 25 m. Find the radius of the
circular field whose area is equal to the difference of the areas of the first and second field.
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Answer:
Let small circle is C
1
and big circle is C
2
.
Given radius of C
1
=5m and radius of C
2
=13m.
Now area of circle is =πr
2
, where r is radius of circle.
Then, area of C
1
=π(5)
2
=25πm
2
−−−−−−(1)
Similarly, area of C
2
=π(13)
2
=169πm
2
−−−−−−(2)
Now, difference of both areas is =169π−25π=144πm
2
−−−−−−−(3)
Let circle C
3
has area equal to difference of area of C
2
and C
1
.
Let radius of C
3
=r
′
.
Then, area of C
3
=144πm
2
{from equation(3)}
So, πr
′
2
=144π
r
′
2
=144
r
′
=12
So, radius of cricle C
3
=12m
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