the radius of one circuler field is 5 and that of other is 3m.find the radius of the circular field whose area is the difference of the areas of the first and second field.
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ANSWER :
The radius is 4 m
EXPLANATION :
R = 5 m
Area = πR² = 3.14 × 25 = 78.5 m²
r = 3 m
Area = πr² = 3.14 × 9 = 28.26 m²
Difference in areas = 78.5 - 28.26
= 50.24 m²
Area = πr²
50.24/3.14 = r²
r² = 16
r = 4
So radius of the circle whose area is difference of the areas of the first and second field is 4 m
Hope it helps.......
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