Question

the radius of oxygen nucleus is 2.8 into 10 power minus 15 metre find the radius of the lead nucleus​

Answer 1

Answer:

Explanation:

=> It is given that,

Radius of oxygen nucleus, R₀ = 2.8 * 10⁻¹⁵ m

Atomic mass of oxygen, A₀ = 16

Atomic mass of lead, Apb = 205

=> As Cube of Radius of nucleus is directly proportional to Atomic mass,

∴ R³ ∝ A

R ∝ (A)¹/³

=> By taking the ratio of  radius of nucleusof oxygen (R₀) and lead (Rpb), we get

R₀/Rpb = (A₀/Apb)¹/³

2.8 * 10⁻¹⁵ / Rpb = (16/205)¹/³

2.8 * 10⁻¹⁵ / Rpb = 2.52/ 5.90

Rpb = 2.8 * 10⁻¹⁵ * 5.90 / 2.52

Rpb = 6.55 * 10⁻¹⁵ m.

Thus, the radius of the lead nucleus​ is 6.55 * 10⁻¹⁵ m.