Physics, asked by Anonymous, 2 months ago

The radius of planet A is double the radius of planet B. If the mass of A is MA, what must be the mass of B so that the value of g on B is double that of its value on A?


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Answered by xXitzSweetMelodyXx
5

Explanation:

answer⤵️

g =  \frac{gm}{ {r}^{2} } \\ ⟹ \: m =  \frac{g {r}^{2} }{g}  \\ here, \frac{ga}{gb}  =  \frac{1}{2}  \\ and \frac{rb}{ra} = 2 \\ ⟹ \frac{ma}{mb} =  \frac{ga}{gb}  ( \frac{rb}{ra} {)}^{2}  \\ ⟹ \frac{mb}{ma} =  \frac{1}{2} (2 {)}^{2}  \\ ⟹ma = 2ma

I hope it's help UH......☺

xXitzSweetMelodyXx

Answered by Anonymous
3

ye le dpzz

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