Question

The radius of small piston is 5.0 cm and that of larger piston is 15 cm. Calculate the
force F, if the mass of the car to be lifted is 1350 kg (g = 9.8 ms-2).​

Answer 1

Answer:

From pascal’s law

P

1

=P

2

A

1

F

1

=

A

2

F

2

πr

1

2

F

1

=

πr

2

2

F

2

F

1

=

r

2

2

F

2

r

1

2

F

1

=

(15×10

−2

)

2

1350×9.8×(5×10

−2

)

2

F

1

=1470N

F

1

=1.47×10

3

N