the radius of sphere is 2+-0.1cm find the percentage error
Answers
Answered by
0
Answer:
Given,
Radius=(2.6±0.1)cm
V=
3
4
πr
3
=
3
4
×3.14×(2.6)
3
=73.6cm
3
Now, in error
V
ΔV
=3(
r
Δr
)
ΔV=v∝3(
r
Δr
)
ΔV=73.6∝3(
2.6
0.1
)
ΔV=8.49cm
3
V
ΔV
×100=
73.6
8.49
×100
=11.53%
∴ Option C is correct.
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