the radius of sphere is 5.3+- 0.1 calculate the percentage error
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Hey,
The volume is given as
V = (4/3)πr3
so, V = (4/3) x 3.14 x 5.33
thus, V = 623.30 cm3
now, the error equation
ΔV/V = 3(Δr/r)
or, ΔV = V x 3(Δr/r)
thus, ΔV = 623.30 x 3x(0.1/5.3)
or error in surface area, ΔV = +/- 35.28 cm3
thus, ΔV/V x 100 = (35.28/623.30) x 100
so, ΔV/V x 100 = 5.66 %
HOPE IT HELPS:-))
The volume is given as
V = (4/3)πr3
so, V = (4/3) x 3.14 x 5.33
thus, V = 623.30 cm3
now, the error equation
ΔV/V = 3(Δr/r)
or, ΔV = V x 3(Δr/r)
thus, ΔV = 623.30 x 3x(0.1/5.3)
or error in surface area, ΔV = +/- 35.28 cm3
thus, ΔV/V x 100 = (35.28/623.30) x 100
so, ΔV/V x 100 = 5.66 %
HOPE IT HELPS:-))
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