The radius of the base and height of a right circular cylinder cone are doubled. The volume of cone isr
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Answer:
Volume of cone(V) = 1/3Πr^2h
R'= 2r
H'=2h
V'= 1/3Π R'^2 H'M
= 1/3 Π (2r)^2 2h
= 1/3 Π 4r^2 2h
= 8/3 Π r^2 h
= 8 V
Hence the new volume is 8 times the old volume
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