Math, asked by navin2003, 1 year ago

the radius of the base is halved nd the height is doubled.what is the ratio of the volume of the new cylinder to that of a original cylinder

Answers

Answered by sonabrainly
6

Answer:

1:2

Step-by-step explanation:



Original Cylinder

Radius = r

Height = h

Volume = 3.14 * r * r * h


New Cylinder

Radius = r/2

Height = 2h

Volume = 3.14 * r/2 * r/2 * 2h


​Therefore,

Required Ratio = New Cylinder : Original Cylinder

                       = (3.14 * r/2 * r/2 * 2h) : (3.14 * r * r * h)

                      = (3.14 * r/2 * r/2 * 2h) / (3.14 * r * r * h)

                      = 1 / 2

                     = 1 : 2    (ans)




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sonabrainly: mark it the brainliest it is there on my answer
Answered by luk3004
3

Answer:

Original Cylinder

Radius = r

Height = h

Volume = 3.14 * r * r * h


New Cylinder

Radius = r/2

Height = 2h

Volume = 3.14 * r/2 * r/2 * 2h


​Therefore,

Required Ratio = New Cylinder : Original Cylinder

                       = (3.14 * r/2 * r/2 * 2h) : (3.14 * r * r * h)

                      = (3.14 * r/2 * r/2 * 2h) / (3.14 * r * r * h)

                      = 1 / 2

                     = 1 : 2    (ans)

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