Question

The radius of the base of a circular cylinder is half and height is doubled find the percentage change in volume

Answer 1

Answer:

Step-by-step explanation:

Je vadun

Answer 2

Answer:

Step-by-step explanation:

Let the radius and height be ready and h initially.

Since the radius is halved and the height is doubled that r/2 and 2h respectively.

The new volume would be π(r/2) ²(2h) =πr²/4×2h=πr²(h) ÷2

Now, we know that% change is equal to

(Final -initial value) ÷initial value×100

So we get [(πr²h/2-πr²h) /πr²h]×100= 50% so the volume is reduced by 50% than the

Initial value

Thank you