the radius of the base of a circular cylinder is halved and height is doubled Find the percentage change in the volume.
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Given,
The radius of the base is halved and the height is doubled.
To find,
The percentage change in the volume.
Solution,
We can simply solve this mathematical problem by using the following mathematical process.
Let, the initial radius = r unit
And, the initial height = h unit
Initial volume = πr²h cubic unit
Final radius = r/2 unit
Final height = 2h unit
Final volume = π × (r/2)² × (2h) = π×r²/4×2h = πr²h/2 cubic unit
Percentage change = 100 × (πr²h/2 ÷ πr²h) = 100 × 1/2 = 50%
Hence, the volume is reduced by 50%.
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Step-by-step explanation:
50% is your answer for this question
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