Math, asked by kindness1073, 11 months ago

the radius of the base of a circular cylinder is halved and height is doubled Find the percentage change in the volume.​

Answers

Answered by Anonymous
2

Given,

The radius of the base is halved and the height is doubled.

To find,

The percentage change in the volume.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

Let, the initial radius = r unit

And, the initial height = h unit

Initial volume = πr²h cubic unit

Final radius = r/2 unit

Final height = 2h unit

Final volume = π × (r/2)² × (2h) = π×r²/4×2h = πr²h/2 cubic unit

Percentage change = 100 × (πr²h/2 ÷ πr²h) = 100 × 1/2 = 50%

Hence, the volume is reduced by 50%.

Answered by guptaanil569
1

Step-by-step explanation:

50% is your answer for this question

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