the radius of the base of a cylinder pillar in a building is 25cm and it's height is 3.5m there are 10 such pillars in the building. what is the cost of painting the pillar if the rate is ₹1.55sq.cm
pls tell
Answers
Answered by
0
Answer:
₹8,52,500
Step-by-step explanation:
to find cost we will first find the total surface area of cylinder
height = 3.5 m = 350 cm
radius = 25 cm
therefore the total surface area of cylinder = 2 pie r (h+r)
= 2 x 22/7 x 25 x 350
= 2 x 22 x 25 x 50
= 55,000 sq.cm
there are 10 pillars so 10x55000 =5,50,000sq.cm
the cost of each sq.cm = ₹ 1.55
= 5,50,000 x 1.55
= ₹ 8,52,500
Answered by
0
Answer:
Given, r=63 cm, h=15 m, h=15×100 cm
Curved surface area =2πrh
=2×
7
22
×63×15×100
=594000cm
2
Total number of pillars =4
CSA of one pillar =594000
CSA of 4 pillars =594000×4=2376000 = 237.6m
2
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