Question

The radius of the base of a cylindrical vessel is 21 cm and its height is 30 cm . The volume of water it can hold _____________ *​

Answer 1

Answer:

$\frac{22}{7} \times {21}^{2} \times 30 = 22 \times 21 \times 3 \times 30 = 41580$

Step-by-step explanation:

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Answer 2

$\bf\huge\blue{\underline{\underline{ Question : }}}$

The radius of the base of a cylindrical vessel is 21 cm and its height is 30 cm . The volume of water it can hold _____________ .

$\bf\huge\blue{\underline{\underline{ Solution : }}}$

★ Given that,

$\tt \rightarrow Radius_{(Cylinder)} = 21\:cm.$

$\tt \rightarrow Height_{(Cylinder)} = 30\:cm.$

★ To find,

• Volume of water it can hold.

★ Formula :

∴ Volume of Cylinder = Volume of water it can hold.

$\boxed{\rm{\red{ Volume_{(Cylinder)} = \pi r^{2}h}}}$

• π = 22/7
• r = Radius of Cylinder.
• h = Height of Cylinder.

$\sf \implies \cfrac{22}{\cancel{7}} \times\cancel{ 21} \times 21 \times 30$

$\sf \implies 22 \times 3 \times 21 \times 30$

$\sf \implies 41580$

$\underline{\boxed{\rm{\purple{ \therefore Volume\:of\:water\:that\:Cylinder\:can\:hold\:is\:41580\:cm^{3}.}}}}\:\orange{\bigstar}$

★ More Information,

➡ TSA of Cylinder = 2πr(r + h)

➡ CSA of Cylinder = 2πrh

➡ Volume of Cylinder = πr²h

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