The radius of the base of a right circular cylinder is halved and the height is doubled. What is the ratio of the volume of the new cylinder to that of the original cylinder?
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Volume of the original cylinder=πr^2h
Radius is halved and height is doubled,
Volume of the new cylinder=π(r/2)^2×2h
Therefore, Ratio of the two cylinders
=πr^2h/π(r/2)^2×2h
=2:1
Radius is halved and height is doubled,
Volume of the new cylinder=π(r/2)^2×2h
Therefore, Ratio of the two cylinders
=πr^2h/π(r/2)^2×2h
=2:1
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