the radius of the base of a right circular cylinder is halved and the height is doubled . what is the ratio of the volume of the new cylinder to that of the original cylinder ?
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Answered by
1
Step-by-step explanation:
ANSWER
Let,
Height of the right circular cylinder =H
Radius of the base of the cylinder =R
Therefore,
Volume of the cylinder, V=πR
2
H
Now,
New height of the right circular cylinder H
′
=2H
New radius of the base of the cylinder R
′
=
2
R
Therefore,
New volume of the cylinder, V
′
=πR
′2
H
′
=π
4
R
2
2H
Therefore,
Required ratio =
V
V
′
=
πR
2
H
π
4
R
2
2H
=
2
1
=1:2
Therefore, the ratio of the volume of the new cylinder to that of the origional cylinder is 2:1.
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Answered by
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Step-by-step explanation:
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