the radius of the base of a right circular cylinder partly filled with water is 5 cm. A sphere of diameter 6 cm is dropped into it and is completely submerged. How much will the level of water rises in the cylinder?
1)1.44
2)2.4
3)1.2
4)2.24
Answers
Answer:
1 cm
Step-by-step explanation:
Given, diameter of speher = 6 cm
⇒ radius of sphere R=26=3cm
Diameter of cylindrical vessel = 12 cm
⇒ radius of cylindrical vessel = r=212=6cm
volume of sphere = 34πR3=34π2(3)2
Volume of cylindrical vessel = πr2h=π×62×h
Here, the volume of sphere = volume increased in the cylindrical vessel.
∴34π(3)3=π(6)2h
h=34×63=6×64×3×3=33=1cm
∴ 1 cm level of water rise in the cylindrical vessel.
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