The radius of the base of a solid cylinder is 5 cm and it's height is 12 cm. A conical hole of the same height and base is made in the cylinder. Find the volume and the whole surface of the remaining solid
Answers
The Whole surface area of the remaining cylinder is S = 210π cm²and the volume of the remaining portion of the cylindrical part is V = 200 π cm³
Step-by-step explanation:
SOLUTION :
Height of the circular Cylinder & cone , h = 12 cm
Base radius of the circular Cylinder & cone , r = 5 cm
Slant height of the cone , l = √r² + h²
l = √5² + 12²
l = 25 + 144
l = √169
l = 13 cm
Now,
Whole surface area of the remaining portion in the circular cylinder ,S = Area of base of the cylinder + curved surface area of cylinder + curved surface area of cone
S = πr² + 2πrh + πrl
S = π(r² + 2rh + rl)
S = π [(5)² + 2( 5)(12) + (5 )(13 )]
S = π[25 + 120 + 65]
S = π× 210
S = 210 π cm²
Hence, the Whole surface area of the remaining cylinder is 210π cm².
Volume of the remaining portion of the circular cylinder = Volume of the cylinder – Volume of the cone
V = ( πr²h – ⅓ × πr²h)
V = ⅔ × πr²h
V = ⅔ × π × 5² × 12 = 2 × π × 25 × 4
V = 200 π cm²
Hence, the Whole surface area of the remaining cylinder is 210π cm²and the volume of the remaining portion of the cylindrical part is V = 200 π cm³
HOPE THIS ANSWER WILL HELP YOU…
MARK ME BRAINLIEST !! ^+^
Answer:
your answer
Step-by-step explanation:
2πrh
2×22/7×5×12
6×22×5×7
you get your answer