Question

the radius of the base of right circular cone is 14 cm and its height is 10.5 cm and find the surface curved surface area of the cone

Answer 1

CSA≈ πr√hsq.+rsq.
≈22/7×14×√10•5sq.+14sq
≈22×2√110•25+196
≈44×√306•25
≈44×17•5
≈770

Answer 2

Answer:

The curved surface area of the cone is $770\:m^{2}$

Step-by-step explanation:

As per the data given in the question,

We have,

Radius of cone = 14 cm

Height of cone = 10.5 cm

So, let slant height =  $l$

As we know,

$l=\sqrt{r^{2} +h^{2} } \\l=\sqrt{14^{2} +10.5^{2} }\\l=17.5$

So, slant height is 17.5 cm

Now, curved surface are = $\pi rl$

$=\frac{22}{7} \times14\times17.5\\=770\:m^{2}$

Hence, the curved surface area of the cone is $770\:m^{2}$

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