The radius of the circle 3X²+by²+4bX-6by+b²=0 is
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Answer:
3x
2
+3y
2
−6x+4y−1=0⇒[(
3
x)
2
−2×
3
×
3
×x+(
3
)
2
]+[(
3
y)
2
+2×
3
×
3
2
y+(
3
2
)
2
]−3−
3
4
−1=0
⇒(
3
)
2
+(
3
y+
3
2
)
2
−
3
16
=0
3(x−1)
2
+3(y+
3
2
)
2
−
3
16
=0
(x−1)
2
+(y+
3
2
)
2
=
3×3
16
=(
3
4
)
2
center (1,
3
−2
) radius =
3
4
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