Question

The radius of the circle
below is 6 cm and <AOB = 60 degress. What
is the length in cm
of the minor arc AB?​

Answer 1

Answer:

12 cm

Explanation:

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Answer 2

Answer:

Area of the segment AXB = Area of the sector OAXB − Area of triangle OAB.

The triangle OAB is an equilateral triangle since the length of sides are equal to the radius of the circle and an angle is 60

0

Area of an equilateral triangle with length of side a=

4

3

a

2

Area of a sector of a circle of radius 'r' and angle θ=

360

θ

πr

2

Hence, Area of segment AXB =

360

60

×3.14×12

2

−

4

1.73

×12

2

=75.36−62.28=13.08sqcm

Explanation:

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