Question

The radius of the circle circumscribing the three vertices of an equilateral triangle is 12 cm. Determine the height (in cm) of the equilateral triangle.

Answer 1

Answer:

r=12, so a/2 = 6v 3 , a = 12V3

height=v3 a/2 =v3x12v 3/2=18

height of the equilateral triangle is

18cm

Answer 2

The required height is 4√3 cm.

Step-by-step explanation:

Since we have given that

Radius of equilateral triangle = 12 cm

So, the side of equilateral triangle would be

$r=\dfrac{a}{\sqrt{3}}\\\\12=\dfrac{a}{\sqrt{3}}\\\\12\sqrt{3}=a$

So, the height of equilateral triangle would be

$h=\dfrac{a}{3}=\dfrac{12\sqrt{3}}{3}=4\sqrt{3}$

Hence, the required height is 4√3 cm.

# learn more:

Prove that the radius of a circle which circumscribes an equilateral triangle of side 12 cm is equal to 4√3 cm.​

https://brainly.in/question/13554994