Question

The radius of the circle is 25 cm and the length of one of its chord is 40cm. Find the distance of the chord from the centre.

Answer 1

ob= 15 cm solution is given in photo

Answer 2

$<b><i><u>$

Hello :)

Here's ur solution -

Given,

r = 25cm

chord AB = 40cm

We know that,

perpendicular from centre bisects the chord.

So the Length of chord AM = 20cm

Since, ∆0AM is a right angled triangle.

We apply -

OA² = AM² + OM² ( Pythagoras theorem)

= 25² = 20² + 0M²

OM = √(25² - 20²)

OM = √(625 - 400)

OM = √225

OM = 15

Hence, the distance of the chord from centre is 15cm.

Hope it helps!