Question

The radius of the circle is 3 m. What is the circumference of another circle, whose area is 49 times that of

the first?

Answer 1

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Answer 2

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Here is your answer.

Radius of first circle = 3m
Area of first circle = $\pi {r}^{2}$

$= \pi \times 3 \times 3 \\ = 9\pi$
Area of second circle = 49 × 9π
$= \frac{49 \times 22 \times 9}{7} \\ \\ = 1386 {m}^{2}$
Now, Area of second circle =$1386 {m}^{2}$
So,

$\pi {r}^{2} = 1386 {m}^{2} \\ \\ {r}^{2} = \frac{1386 \times 7}{22} \\ \\ {r}^{2} = 441 \\ \\ r = \sqrt{441} \\ r = 21m$

Therefore, The radius of second circle is 21m.

Now, Circumference of circle = 2πr


$=\frac{2 \times 22 \times 21}{7} \\ = 132m$

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