Question

The radius of the circle is 6 cm The perpendicular distance from the centre of the circle to the
chord which is 8 cm in the length is ?​

Answer 1

Step-by-step explanation:

O is centre.

Since we know that perpendicular from centre on a chord bisects it.

So, AP=BP

and in △OPA,

r

2

=(OA)

2

=(OP)

2

+(AP)

2

(6)

2

=(OP)

2

+(

2

AB

)

2

36=(OP)

2

+3

2

(OP)=36−9

OP=

27

=3

3