Question

The radius of the circle passing through the point (2, 6) two of whose diameters are x + y = 6 and x + 2y = 4 is ​

Answer 1

Answer:

Given equation x + 3y - k = 0. Substitute x = 2 and y = -1 then we get ⇒ 2 - 3 - k = 0 k = -1. when k = -1, x = 2 and y = -1 is a solution of x + 3y - k = 0.