Question

the radius of the circle with centre O' is 6cm. a tangent PR at point P on the circle meet a line drawn from O' at point R such that OR=10cm therefore the length of PR=____cm
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Answer 1

In quadrilateral PQOR, ∠P+∠PQO+∠PRO+∠QOR=360

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But ∠PQO=∠PRO=90

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(Tangent is perpendicular to radius at point of contact)

Thus, 50

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+90

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+90

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+∠QOR=360

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So, ∠QOR=130

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In triangle OQR, ∠OQR+∠ORQ+∠QOR=180

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Hence, 2.∠OQR+∠QOR=180

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(because, ∠OQR=∠ORQ; (since OQ=OR, radii ))

Thus, 2.∠OQR+130

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=∠180

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So, ∠OQR=25

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Step-by-step explanation:

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