Question

The radius of the circle x2 + y2 + 18x + 24y =
O is​

Answer 1

Step-by-step explanation:

Given equation of circle os

${x}^{2} + {y}^{2} + 18x + 24y = 0$

Here, 2g = 18 , 2f = 24 and c = 0

=> g = 9 , f = 12 and c = 0

So, the radius of the circle is

$r = \sqrt{ {g}^{2} + {f}^{2} - c}$

$= > r = \sqrt{ {9}^{2} + {12}^{2} - 0 }$

$= > r = \sqrt{81 + 144}$

$= > r = \sqrt{225}$

$= > r = 15$

Answer 2

Step-by-step explanation:

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