the radius of the circular end of a frustum of height 12cm are 15cm and 6cm respectively,find the lateral surface area and total surface area of the frustum
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Answer:
Step-by-step explanation:
Given
Diameter to top of bucket = 40 cm
Radius (r1) = 402=20cm
Diameter of bottom part of the bucket = 20 cm
Radius (r2) =302=10cm
Depth of the bucket (h) = 12 cm
Volume of the bucket = Π3(r21+r22+r1r2)h
= Π3(202+102+20×10)12
= 8800cm3
Let ‘L’ be slant height of the bucket
=>L = (r1−r2)2+h2−−−−−−−−−−−−√
=>L = (20−10)2+122−−−−−−−−−−−−−√
=>L = 15.620cm
Total surface area of bucket = Π(r1+r2)×L+Π×r22
= Π(20+10)×15.620+Π×102
= 132061√+22007
= 17.87dm2
Given that cost of tin sheet used for making bucket per dm2 = Rs 1.20
So total cost for 17.87dm2 = 1.20×17.87
= Rs 21.40.
∴
Cost for 17.87dm2 = Rs 21.40
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