the radius of the cone is increased by 50% and height of the cone remains the same,the volume is increased by
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Answer: 125%
Explanation:
Let the initial radius and height = 10 each
Volume of a Cone = (1/3)πr^2h
Initial Volume = (1/3)π10^2*10 = 1000π/3
The new radius = 15
New Volume = (1/3)π15^2*10 = 2250π/3
Increase in Volume = 125%
Explanation:
Let the initial radius and height = 10 each
Volume of a Cone = (1/3)πr^2h
Initial Volume = (1/3)π10^2*10 = 1000π/3
The new radius = 15
New Volume = (1/3)π15^2*10 = 2250π/3
Increase in Volume = 125%
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