Question

The radius of the cylinder is half of its height and area of inner part is 616 sq.cm. How many liters of milk can it contain.

Answer 1

$given \\ \\ r = \frac{h}{2} \: \\ and \\ \\ 2\pi \: rh + \pi \: r {}^{2} = 616m {}^{2} \\ \\ 2\pi \times \frac{1}{2} h \times h + \pi \times \frac{1}{4} h {}^{2} = 616 \\ \\ \frac{5}{4} \times \frac{22}{7} h {}^{2} = 616 \\ \\ h {}^{2} = 616 \times \frac{28}{110} = \frac{28 \times 28}{5} \\ \\ volume = \pi \: r {}^{2} h \\ \\ = \frac{22}{7} \times \frac{1}{4}h {}^{2} \times h \\ \\ = \frac{22}{7 } \times \frac{1}{4} \times \frac{28 \times 28}{5} \times \frac{28}{ \sqrt{5} } \\ \\ ( \frac{22 \times 28 \times 28}{25} \times \sqrt{5} )cm {}^{3 } \\ \\ ( \frac{22 \times 28 \times 28 \times 223}{25 \times 100} ) \\ \\ = 1.53 \: lit$

Answer 2

Hi dear here is your answer.