Question

the radius of the earth in 6 into 10 raise to power 6 metre at what depth from the centre of the earth the weight of the body becomes half​

Answer 1

3×10⁶ m

Explanation:

Gravitational acceleration below the earth's surface can be calculated as follows:

$g'=g(1-\frac{d}{R})$

weight at depth d is half which means

$g'=\frac{g}{2}$

substitute the values:

$\frac{g}{2}=g(1-\frac{d}{R})\\\frac{1}{2}=(1-\frac{d}{R})\\d=\frac{R}{2}$

$R=6\times 10^6 m\\\Rightarrow d=3\times 10^6 m$

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