Question

the radius of the earth is 630km and the value of accleration due to gravity on the earth's surface is 9.8m/s^2. calculate the accleration due to gravity at the top of Mt.everest. The height of mt. everest is 8848 from the earth's surface.

Answer 1

Answer:

9.5ms

9.5ms −2

9.5ms −2

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1−

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′ =9.8(1−

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′ =9.8(1− 6400

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′ =9.8(1− 64002×100

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′ =9.8(1− 64002×100

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′ =9.8(1− 64002×100 )

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′ =9.8(1− 64002×100 )⇒g

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′ =9.8(1− 64002×100 )⇒g ′

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′ =9.8(1− 64002×100 )⇒g ′

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′ =9.8(1− 64002×100 )⇒g ′ =9.8(1−

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′ =9.8(1− 64002×100 )⇒g ′ =9.8(1− 32

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′ =9.8(1− 64002×100 )⇒g ′ =9.8(1− 321

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′ =9.8(1− 64002×100 )⇒g ′ =9.8(1− 321

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′ =9.8(1− 64002×100 )⇒g ′ =9.8(1− 321 )=9.49m/s

9.5ms −2 Acceleration due to gravity changes with the height from Earth's surface as:g ′ =g(1− R2h )⇒g ′ =9.8(1− 64002×100 )⇒g ′ =9.8(1− 321 )=9.49m/s 2