Question

The radius of the earth is 6400 km and g=10m//sec^(2). In order that a dody of 5 kg weight zero at the equator, the angular speed of the earth is

Answer 1

Answer:

Due to earth rotation,

g' = g – w2 cos2λ R

at equator λ = 0 hence

g' = g – w2R

for zero weight g' = 0

hence

0 = g – w2R

w2R = g

w = √(g/R) = √[(10) / (6400 × 103)]

= [1 / (800)] rad/s