Question

the radius of the earth is about 6370 km an object of mass 30 kg is taken to height of 230 km above the earth what is the mass of the body ? what is the acceleration to gravity at this height​

Answer 1

Answer:

Acceleration due to gravity at a depth is given by

g'=g(1-d/R)

g'= g(1-32/6400)

g'=g(1-1/200)

g'-g=(1/200)g

(g'-g)/g =1/200

If m is the mass of the body,then mg and mg' will be the weight of the body on the surface of the earth and at a depth of 32km below the surface of the earth,then,

% decrease in weight ={(mg'-mg)/mg}x 100

={(g'-g)/g}x100

=(1/200) x 100=0.5%

Explanation: