Question

The radius of the earth is decreased by 1% and mass remains same then the acceleration due to gravity changes by

Answer 1

Answer:

F = G M m / R^2 = k m / R^2 = m g   where g is acceleration due to F

g = k R^-2

dg = -2 k R^-3 dR

dg / g = (-2 k / R^3) / (k / R^2) dR = -2 dR / R

dg / g = -2 * (-.01) = .02

So g increases by 2%