Math, asked by yogi5292, 6 months ago

The radius of the interval [-1,3] is​

Answers

Answered by bg5950669
1

Answer:

ANSWER

f

(x)=12(x

2

−1)

f

(x)=0 at x=±1

f

(x)<0 If ∣x∣<1

f

(x)>0 If ∣x∣>1

f(x) is min when x=1

f(1)=−8

f(x) is max either at x=−1 or x=3

f(−1)=8 , f(3)=72

So image [-8, 72] in [-1, 3]

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