Question

the radius of the moon is 1.7 into 10 ^ 6 metre and its mass is 7.35 into 10 to the power of 22 kg what is the acceleration due to gravity on the surface of the Moon take g is equal to 6.67 into 10 ^ - 11 Newton metre square per kg square .solve if u r perfect in physics

Answer 1

Hey buddy,

# Answer- g = 1.7 m/s^2

# Given-
Mass of moon M=7.35×10^22kg
Radius of moon R=1.7×10^6m
Gravitational constant G=6.67×10^-11Nm^2/kg^2
g = ?

# Explaination-
Gravitational acceleration at moon surface is given by
g = GM/R^2
g = 6.67×10^-11 × 7.35×10^22 / (1.7×10^6)^2
g = 1.7 m/s^2

Gravitational acceleration at moon surface is 1.7 m/s^2.

Answer 2

Answer:

Now g=Gm/R^2

Explanation:

here, R = 1.7*10^6m ;. M=7.35*10^22kg

G= 6.67*10^-11N m^2 kg ^-2

g= 6.67*10^-11*7.35*10^22 / (1.7*10^6)^2

1.696m s^-2