Question

The radius of the nearly circular orbit of mercury is 5.8×10^10 m and its orbital period 88 days if hypothetical planet has an orbital period of 55 days what is the radius of its circular orbit

Answer 1

Answer-
Let  us assume masses of both the planet is same As per Kepler's lawT² α r³T² = k × r³

Rp/Rm = (Tp/ Tm)∧2/3
Rp = Rm (Tp/ Tm)∧2/3

put the values in the equation
Rp = (5.8 × 10∧10) (55/ 85)∧2/3
     = 4.24 × 10∧10 days
radius of circuit is 4.24 × 10∧10 days

Answer 2

The radius of the nearly circular orbit of mercury is 5.8×10^10 m and its orbital period 88 days if hypothetical planet has an orbital period of 55 days        Note ---- Hope my answer helps you and please do the calculation I have done it and it is correct