Question

The radius of the third orbit of He+ will be

Answer 1

$\bigstar$ Answer:

⇒ Formula to be used here,

$\boxed{\sf{Radius \;of\; Bohr's\; orbit =\dfrac{0.529*n^2}{Z}\;A^0}}$

Where,

$\sf n$ = Prinicipal quantum number of orbit.

$\sf Z$ = Atomic number.

$\checkmark$ $\sf 3^r^d$ shell of $\sf He^+$ means $\boxed{\sf{n=3}}$

$\checkmark$ Z for $\sf He^+$ is $\boxed{\sf{Z=2}}$

Substituting the above values in the given formula

We get,

$\implies \sf{\dfrac{0.529*3^2}{2}\;A^0 }$

Therefore,

Radius for 3rd shell of $\sf He^+$ is,

$\purple {\large{\boxed{\sf{ 2.3805 \;A^0}}}}$