Question

The radius of the top and bottom of a bucket of slant height 35 cm are 25 cm and 8cm.

The curved surface of the bucket is:​

Answer 1

Slant Height (L) = 45 cm

Radius of the top of the bucket (R) = 28 cm

Radius of the bottom of the bucket (r) = 7 cm

Therefore,

CSA of the bucket = πL (R+r)= 22/7 × 45 ( 28+7) = 22/7 × 45 × 35

=> 22 × 45×35 /7 = 34650/7 = 4950 cm².

Answer 2

Answer:

The curved surface area of the bucket is 3630 sq cm.

Step-by-step explanation:

Bucket's - top radius (r1)= 25cm

    bucket   bottom radius(r2) = 8cm

      bucket     slant height (l) = 35cm

We are asked to find  the curved surface of the backet

Curved surface area  of a bucket = πl(r1 + r2)

Here 'l' is slant height, 'r1' & 'r2' are top and bottom radius respectively.

'Curved surface area = πl(r1 + r2)' {the value of π is 22/7}

                                   $=\frac{22}{7} *35(25 + 8)\\=22*5(33)\\=22*165\\=3630cm^{2}$

Therefore, the curved surface area of the bucket is 3630 sq cm.